3[5-3(y-4)]=2y+7

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Solution for 3[5-3(y-4)]=2y+7 equation:


Simplifying
3[5 + -3(y + -4)] = 2y + 7

Reorder the terms:
3[5 + -3(-4 + y)] = 2y + 7
3[5 + (-4 * -3 + y * -3)] = 2y + 7
3[5 + (12 + -3y)] = 2y + 7

Combine like terms: 5 + 12 = 17
3[17 + -3y] = 2y + 7
[17 * 3 + -3y * 3] = 2y + 7
[51 + -9y] = 2y + 7

Reorder the terms:
51 + -9y = 7 + 2y

Solving
51 + -9y = 7 + 2y

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '-2y' to each side of the equation.
51 + -9y + -2y = 7 + 2y + -2y

Combine like terms: -9y + -2y = -11y
51 + -11y = 7 + 2y + -2y

Combine like terms: 2y + -2y = 0
51 + -11y = 7 + 0
51 + -11y = 7

Add '-51' to each side of the equation.
51 + -51 + -11y = 7 + -51

Combine like terms: 51 + -51 = 0
0 + -11y = 7 + -51
-11y = 7 + -51

Combine like terms: 7 + -51 = -44
-11y = -44

Divide each side by '-11'.
y = 4

Simplifying
y = 4

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